Integrand size = 23, antiderivative size = 34 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {B x}{a}+\frac {(A-B) \sin (c+d x)}{d (a+a \cos (c+d x))} \]
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Time = 0.06 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2814, 2727} \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {(A-B) \sin (c+d x)}{d (a \cos (c+d x)+a)}+\frac {B x}{a} \]
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Rule 2727
Rule 2814
Rubi steps \begin{align*} \text {integral}& = \frac {B x}{a}-(-A+B) \int \frac {1}{a+a \cos (c+d x)} \, dx \\ & = \frac {B x}{a}+\frac {(A-B) \sin (c+d x)}{d (a+a \cos (c+d x))} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(76\) vs. \(2(34)=68\).
Time = 0.25 (sec) , antiderivative size = 76, normalized size of antiderivative = 2.24 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=-\frac {\sin (c+d x) \left (B \arcsin (\cos (c+d x)) (1+\cos (c+d x))+(-A+B) \sqrt {\sin ^2(c+d x)}\right )}{a d \sqrt {1-\cos (c+d x)} (1+\cos (c+d x))^{3/2}} \]
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Time = 0.93 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.82
method | result | size |
parallelrisch | \(\frac {d x B +\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (A -B \right )}{a d}\) | \(28\) |
derivativedivides | \(\frac {A \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-B \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 B \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}\) | \(45\) |
default | \(\frac {A \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-B \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 B \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}\) | \(45\) |
risch | \(\frac {B x}{a}+\frac {2 i A}{d a \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}-\frac {2 i B}{d a \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}\) | \(54\) |
norman | \(\frac {\frac {B x}{a}+\frac {B x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}+\frac {\left (A -B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}+\frac {\left (A -B \right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}}{1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )}\) | \(85\) |
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Time = 0.32 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.26 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {B d x \cos \left (d x + c\right ) + B d x + {\left (A - B\right )} \sin \left (d x + c\right )}{a d \cos \left (d x + c\right ) + a d} \]
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Time = 0.36 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.44 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\begin {cases} \frac {A \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{a d} + \frac {B x}{a} - \frac {B \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{a d} & \text {for}\: d \neq 0 \\\frac {x \left (A + B \cos {\left (c \right )}\right )}{a \cos {\left (c \right )} + a} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 73 vs. \(2 (34) = 68\).
Time = 0.29 (sec) , antiderivative size = 73, normalized size of antiderivative = 2.15 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {B {\left (\frac {2 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a} - \frac {\sin \left (d x + c\right )}{a {\left (\cos \left (d x + c\right ) + 1\right )}}\right )} + \frac {A \sin \left (d x + c\right )}{a {\left (\cos \left (d x + c\right ) + 1\right )}}}{d} \]
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Time = 0.30 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.26 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {\frac {{\left (d x + c\right )} B}{a} + \frac {A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - B \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a}}{d} \]
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Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.88 \[ \int \frac {A+B \cos (c+d x)}{a+a \cos (c+d x)} \, dx=\frac {\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (A-B\right )}{a}+\frac {B\,d\,x}{a}}{d} \]
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